A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!

Sep 25, 2010 · That second memory address, then, is expected to hold an int. Do note that, while you are declaring a pointer to an int, the actual int is not allocated. So it is valid to say int *i = …

Nov 25, 2013 · It is a pointer to function that returns int* and accepts int* and pointer to function that returns int* (and accepts undefined number of parameters; see comments).

int* i, int * i, int*i, and int *i are all exactly equivalent. This stems from the C compiler (and it's compatible C like systems) ignoring white space in token stream generated during the process …

Jan 28, 2012 · The real reason that this can happen is that C is a weakly typed language. But unsigned int and int are really different.

64 I prefer int* i because i has the type "pointer to an int", and I feel this makes it uniform with the type system. Of course, the well-known behavior comes in, when trying to define multiple …

Aug 24, 2016 · The question "what is the difference between int* and int []?" is a less trivial question than most people will think of: it depends on where it is used. In a declaration, like …

Jul 1, 2021 · int (*f)(int, int) = dlsym( shared_lib, "foo" ); They're also handy for building table-driven code - I once wrote a utility to load and parse different types of data files from various …

In C#, int and Int32 appear to be the same thing, but I've read a number of times that int is preferred over Int32 with no reason given. Are the two really the same? Is there a reason …

I saw someone using this in one answer: void methodA(const int*& var); I couldn't understand what the argument means. AFAIK: const int var => const int value which can't …